In this next section I start to work with equations that are fractions. I first start with some basic ones consisting of two terms, one of which is a fraction.

Examples in the video

Solve the following:

  1. \dfrac{x}{3} = 4
  2. \dfrac{8}{x} = 4
  3. \dfrac{{5x - 3}}{4} = 2
  4. 3 = \dfrac{{15x + 2}}{{4x}}
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How to solve a linear equation (5) - Fractional Type : ExamSolutions Maths Revision
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I continue to look at fractional equations consisting of one term which is a fraction but in the denominator of that fraction there are two terms.

Examples in the video

Solve the following:

  1. \dfrac{{8x - 1}}{{x + 2}} = 5
  2. 7 = \dfrac{{3 - 4x}}{{2x - 5}}
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How to solve a linear equation (6) - Fractional Type : ExamSolutions Maths Revision
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In this next video I now look at fractional equations consisting of at least 3 terms where one of them is a fraction.

Examples in the video

Solve the following:

  1. \dfrac{{3x}}{5} - 2x = 4
  2. 5x - \dfrac{3}{4} = x + 2
  3. 5 - \dfrac{3}{{2x}} = 4
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How to solve a linear equation (7) - Fractional Type : ExamSolutions Maths Revision
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I now look at fractional equations consisting of at least 2 terms which are fractions.

Examples in the video

Solve the following:

  1. \dfrac{{4x - 7}}{{10}} = \dfrac{{x - 3}}{5}
  2. \dfrac{{3x - 2}}{4} - \dfrac{{x - 2}}{3} = \dfrac{{2x - 1}}{6}
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How to solve a linear equation (8) - Fractional Type : ExamSolutions Maths Revision
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This is the last in this series where I now look at fractional equations where x appears in the denominator of both fractions.

Examples in the video

Solve the following:

  1. \dfrac{3}{x} = \dfrac{5}{{x + 2}}
  2. \dfrac{7}{{5x - 3}} = \dfrac{2}{{x + 1}}
Video Thumbnail
How to solve a linear equation (9) - Fractional Type : ExamSolutions Maths Revision
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