# Integrating products of the form f[g(x)]g'(x) by inspection

Here I show you how to handle integrals which take on the form commonly known as f[g(x)]g'(x) and can be evaluated by inspection

In order to fully understand this, you should be able to differentiate expressions by the chain rule

##### Integrals of the form f[g(x)]g'(x) : ExamSolutions Maths Revision

## Summary Exercise

##### Integrals of the form f[g(x)]g'(x) (Summary Exercise) : ExamSolutions Maths Revision

## Extension to Af[g(x)]g'(x) where A is a constant

##### Integrals of the form Af[g(x)]g'(x) : ExamSolutions Maths Revision

## Summary Exercise

##### Integrals of the form Af[g(x)]g'(x) (Summary Exercise) : ExamSolutions Maths Revision

Stuart the ExamSolutions Guy
2017-04-26T12:39:56+00:00