Here I show you how to handle integrals which take on the form commonly known as f[g(x)]g'(x) and can be evaluated by inspection

In order to fully understand this, you should be able to differentiate expressions by the chain rule

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Integrals of the form f[g(x)]g'(x) : ExamSolutions Maths Revision

Summary Exercise

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Integrals of the form f[g(x)]g'(x) (Summary Exercise) : ExamSolutions Maths Revision

Extension to Af[g(x)]g'(x) where A is a constant

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Integrals of the form Af[g(x)]g'(x) : ExamSolutions Maths Revision

Summary Exercise

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Integrals of the form Af[g(x)]g'(x) (Summary Exercise) : ExamSolutions Maths Revision